Ravens quarterback Lamar Jackson named AFC Offensive Player of the Week

OWINGS MILLS – The accolades keep piling up for Ravens quarterback Lamar Jackson.

Jackson was named the AFC Offensive Player of the Week for his performance in a 56-19 victory over the Miami Dolphins on Sunday.

Jackson completed 18 of 21 passes (85.7%) for 321 yards and five touchdowns, finishing with a perfect passer rating (158.3) for the third time in his career.

He threw touchdown passes to players from every skill position – running back Justice Hill, wide receiver Zay Flowers, tight end Isaiah Likely (two), and fullback Patrick Ricard.

It was the second time Jackson has won the award this season. In Week 7, Jackson garnered the honors after completing 21 of 27 passes for a season-high 357 yards and three touchdowns in a 38-6 victory over the Lions. He also ran for a 7-yard touchdown.

It is the 10th time in his career that Jackson has won AFC Offensive Player of the Week honors.

Jackson is the third Ravens player to be named player of the week. Tylan Wallace won for special teams in Week 14 and safety Kyle Hamilton was the best defensive player in Week 15.

Jackson was named NFL MVP in 2019, and is the favorite to win that award again this season.

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